Question

resolvendo a inequaca
$\sqrt{4 - x } < \sqrt{x - 2} \: obtemos...$
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Answer 1

√4-x < √x-2

(√4-x)² < (√x-2)²

4-x < x-2

-x -x < -2 -4

-2x < -6 ===> *(-1)

2x > 6

x > 6/2

x > 3. ===> 3 < x ≤ 4