Question

resolva:

$a) {y}^{2} = 16$

$b) {3}^{2} = 27$


$c) {9}^{2} = 900$
$d) - 36 + {4}^{2} = 0$
$e) {x}^{2} + 4 - = 4x$
$f) \frac{4}{3} {x}^{2} - \frac{2}{3} x = 0$

Answer 1

boa noite princesa !!!!

$a) \\ \\ y {}^{2} = 16 \\ y = 4 \\ y = - 4 \\ y1 = - 4 \\ y2 = 4 \\ \\ b) \\ \\ 3 {}^{2} = 27 \\ 9 = 27 \\ = falso \\ \\ c) \\ \\ 9 {}^{2} = 900 \\ 729 = 900 \\ = falso \\ \\ d) \\ \\ - 36 + 4 {}^{2} = 0 \\ - 36 + 16 = 0 \\ - 20 = 0 \\ = falso \\ \\ e) \\ \\ x {}^{2} + 4 - = 4x \\ x {}^{2} + 4 + 4x = 0 \\ x {}^{2} + 4x + 4 = 0 \\ (x + 2) {}^{2} = 0 \\ x + 2 = 0 \\ x = - 2 \\ \\ f) \\ \\ \frac{4}{3} x {}^{2} - \frac{2}{3}x = 0 \\ 4x {}^{2} - 2x = 0 \\ 2x \times (2x - 1) = 0 \\ x \times (2x - 1) = 0 \\ x = 0 \\ 2x - 1 = 0 \\ x1 = 0 \\ x2 = \frac{1}{2}$

espero que eu tenha conseguido te ajudar princesa..