Question

Resolva pelo delta


X²-4x=0

X²-x=0

Answer 1

X²-4x=0
A=1. B=-4. C=0

Δ=b²-4ac
Δ=(-4)²-4.1.0
Δ=16

X=-b±√Δ/2a
X=-(-4)±√16/2.1
X=4±4/2
X'=4+4/2=8/2=4
X”=4-4/2=0/2=0

X²-x=0
A=1. B=-1. C=0

Δ=(-1)²-4.1.0
Δ=1

X=-(-1)±√1/2.1
X=1±1/2
X'=1+1/2=2/2=1
X"=1-1/2=0/2=0



Espero ter ajudado :-)

Answer 2

Boa tarde Fabio

x² - 4x = 0

delta
d² = 4² = 16
d = 4

x1 = (4 + 4)/2 = 8/2 = 4
x2 = (4 - 4)/2 = 0

x² - x = 0

delta
d² = 1
d = 1

x1 = (1 + 1)/2 = 1
x2 = (1 - 1)/2 = 0