Question

resolva o cálculo abaixo:

Answer 1

$\frac{5x}{2} + \frac{3x}{3} = \frac{x}{7} + \frac{15}{8} \\ \\ \frac{5x}{2} + \frac{\cancel{3}}{\cancel{3}x} = \frac{x}{7} + \frac{15}{8} \\ \\ \frac{5x}{2} + \frac{x}{1} - \frac{x}{7} = \frac{15}{8} \\ \\ \frac{47x}{14} = \frac{15}{8} \\ \\ \frac{\cancel{14} \times 47x}{\cancel{14}} = \frac{14 \times 15}{8} \\ \\ 47x = \frac{105}{4}$

$x = \frac{105}{4} \div 47 \\ \\ x = \frac{105}{4} \times \frac{1}{47} \\ \\ x = \frac{105}{4 \times 47} \\ \\ x = \frac{105}{188}$

$\mathcal{Bons \: estudos } \\ \displaystyle\int_ \empty ^ \mathbb{C}     \frac{ - b \: ± \:  \sqrt{ {b}^{2} - 4 \times a \times c } }{2 \times a} d{ t } \boxed{ \boxed{ \mathbb{\displaystyle\Re}\sf{ \gamma  \alpha }\tt{ \pi}\bf{ \nabla}}}$