Question

Resolva Essa Equação X² +6 X + 8=0
Na forma de baskara

Answer 1

.
$x^{2} +6x+8=0 \\ \\ a=1 \\ b=6 \\ c=8 \\ \\ \Delta=b^2-4ac \\ \Delta=6^2-4(1)(8) \\ \Delta=36-32 \\ \Delta=4 \\ \\ x=- \frac{b\pm \sqrt{\Delta} }{2a} = \frac{-6\pm \sqrt{4} }{2} = \frac{-6\pm2}{2} \\ \\ x'= \frac{-6+2}{2} =- \frac{4}{2} =-2 \\ \\ x"= \frac{-6-2}{2} =- \frac{8}{2} =-4$