Question

Resolva, em R, as equações abaixo.

Answer 1

b)

$\frac{1}{3-x} +\frac{6}{(x -3)(x+3)} = \frac{2}{x}\\ \\\frac{-1}{x -3} +\frac{6}{(x -3)(x+3)} = \frac{2}{x}\\ \\\frac{-(x-3)(x +3) +6(x -3)}{(x -3)(x +3)(x -3)} = \frac{2}{x}\\ \\\frac{(x -3) * (-(x +3) + 6)}{(x -3) * ((x -3) * (x+3))} = \frac{2}{x}\\ \\\frac{(-x +3)}{(x -3)(x+3)} = \frac{2}{x}\\ \\\frac{-1(-x+3)}{-1(x-3)(x+3)} = \frac{2}{x}\\ \\\frac{-1}{(x +3)} = \frac{2}{x}\\ \\ -x = 2x +6\\-3x = 6\\x = -2$