resolva as expressões a)64⅓+81½-12 b)1 9/7-10+121½ c)625¼-1024¹/10+100½??
Soluções para a tarefa
Respondido por
50
a)64^1/3 +81^1/2 -12
∛64 + √81 - 12 =
∛4³ + 9 - 12 =
4 + 9 - 12 =
13 - 12 = 1
b)1^9/7 - 10 + 121^1/2 =
⁷√1^9 - 10 + √121 =
1 - 10 + 11 = -10 + 11 = 1
c)625^1/4 - 1024^1/10 + 100^1/2 =
⁴√625 - ¹⁰√1024 + √ 100 =
⁴√5⁴ - ¹⁰√2¹⁰ + 10 =
5 - 2 + 10 = -2 + 15 = 13
∛64 + √81 - 12 =
∛4³ + 9 - 12 =
4 + 9 - 12 =
13 - 12 = 1
b)1^9/7 - 10 + 121^1/2 =
⁷√1^9 - 10 + √121 =
1 - 10 + 11 = -10 + 11 = 1
c)625^1/4 - 1024^1/10 + 100^1/2 =
⁴√625 - ¹⁰√1024 + √ 100 =
⁴√5⁴ - ¹⁰√2¹⁰ + 10 =
5 - 2 + 10 = -2 + 15 = 13
Perguntas interessantes