Question

Resolva as equações a seguir.

A)
$\frac{1}{2}^{x + 1 } = \frac{1}{64}$
B)
$4 ^{x} = \frac{1}{128}^{ - x + 1}$

Obs: Coloquem os cálculos fazendo favor. Obrigada

Answer 1

(1/2)×+1 = 1/64

(1/2)×+1 = 1/2^6
2-¹(×+1) = 2-¹(6)
2-×-1 = 2^-6
-x-1 = -6
-x = -6+1
-x = -5 ( •-1)
x = 5


b) 4× = (1/128)^-x+1

2²× = (1/2^7)^-x+1
2²× = 2^-7(-×+1)
2x = 7x-7
2x-7x = -7
-5x = -7 ( •-1)
5x = 7
x = 7/5