Question

Resolva a seguinte equação do 2º grau.

Answer 1

${x}^{2} + \frac{5x}{2} - \frac{3}{2} = 0 \times 2 \\ 2 {x}^{2} + 5x - 3 = 0$

$\Delta={b}^{2}-4ac\\\Delta={5}^{2}-4.2.(-3)=25+24=49$

$x=\dfrac{-b\pm\sqrt{\Delta}}{2a} \\x=\dfrac{-5\pm7}{4}$

$\boxed{\boxed{\mathsf{x'=\dfrac{-5+7}{4}=\dfrac{1}{2}}}}$

$\boxed{\boxed{\mathsf{x''=\dfrac{-5-7}{4}=-3}}}$