Question

Resolva a inequação
√2x >x²

Answer 1

$\sqrt{2}x > x^2$

$x^{2}< \sqrt{2}x$

$x^{2} - \sqrt{2}x <0$

$x(x- \sqrt{2)}<0$

x<0  e  x-$\sqrt{2}=0-->x< \sqrt{2}$