Question

RESOLVA A EQUAÇÃO DO 2º GRAU x²+x-20=0

Answer 1

$\LARGE\tt{} {x}^{2} + x - 20 = 0 \\ \LARGE\tt{} {x}^{2} + 5x - 4x - 20 = 0 \\ \LARGE\tt{}x \times\left(x + 5\right) - 4\left(x + 5\right) = 0 \\ \LARGE\tt{}\left(x + 5\right) \times \left(x - 4\right) = 0 \\ \LARGE\tt{}x + 5 = 0 \\ \LARGE\tt{}x - 4 = 0 \\ \LARGE\tt{}x = - 5 \\ \LARGE\tt{}x = 4 \\ \LARGE\tt{} x_{1} = - 5 \\ \LARGE\tt{} x_{2} = 4 \\ \\ \\ \\ \LARGE\tt{}s \{ x_{1} = - 5 \} \\ \LARGE\tt{}s \{ x_{2} = 4 \}$

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