Question

resolva a equaçao:
a)3x²+15x=0
b)2y²-y/3=0

Answer 1

 a)
3x²+15x=0
coloca em evidência o x, assim:
x(3x +15) = 0

x'= 0

(3x +15) = 0
3x +15 = 0
x = 15/3
x''= 5

b)
2y²-y/3=0
(6y² - y)/3 = 0

6y² - y = 0
y(6y -1) =0

y' = 0

(6y -1)=0
6y -1 = 0
6y = +1
y' = 1/6

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Answer 2

a)3x²+15x=0

x(3x +15) = 0

x= 0
(3x +15) = 0
3x +15 = 0
x = 15/3
x= 5

S{0 ;  5}

b)2y²-y/3=0    mmc = 3

(6y² - y)/3 = 0    elimina denominador 3

6y² - y = 0
y(6y -1) =0

y = 0
(6y -1)=0
6y -1 = 0
6y = +1
y = 1/6


S{0 ; 1/6}