Question

resolva a equação:
(2x-4)²=1
pfv

Answer 1

(2x-4)² = 1

4x² - 16x + 16 = 1

4x² - 16x + 15 = 0 
Δ = 256 - 240
Δ = 16

x = 16 +-√16/8
x = 16 +-4/8

x' = 16+4/8
x' = 20/8 = 5/2 

x'' = 16-4/8
x'' = 12/8 = 3/2                                 ok

Answer 2

Vamos lá :

$(2x-4) ^2 = 1 \\ \\ 2x-4 =~\pm~\sqrt{ 1} \\ \\ 2x - 4 = ~\pm~1 \\ \\ 2x = 4~\pm~1 \\ \\ \\ x = \frac{4~\pm~1}{2} \\ \\ \\ x' = \frac{4 + 1}{2} ~~~~~~~~x'' = \frac{4 - 1}{2}\\ \\ x' = \frac{5}{2}~~~~~~~~~~~x''= \frac{3}{2} \\ \\ \\ \\ S = \{\frac{3}{2},\frac{5}{2}\}$

Espero ter ajudado !!