Matemática, perguntado por wellingtonbastos482, 4 meses atrás

Resolva;
A)2/3+1/7+3/2+1/10
B)6/4+1/3-1/7-2/16+4/21
C)3/2+1/2+6/11+3/2-10/7
D)4/5-1/2-2/3+6/7+10/8

Anexos:

Soluções para a tarefa

Respondido por marizafigueiredo62
0

Resposta:

A) 253/105; B) 295/168; C) 403/154; D) 25/21.

Explicação passo a passo:

A)2/3 + 1/7 + 3/2 + 1/10 =

Igualando os denominadores:

140/210 + 30/210 + 315/210 + 21/210 =

170/210 + 336/210 =

506/210 = 253/105.

B) 6/4 + 1/3 - 1/7 - 2/16 + 4/21 =

Igualando os denominadores:

504/336 + 112/336 - 48/336 - 42/336 + 64/336 =

616/336 - 90/336 + 64/336 =

526/336 + 64/336 =

590/336 = 295/168.

C)3/2 + 1/2 + 6/11 + 3/2 - 10/7 =

Igualando os denominadores:

231/154 + 77/154 + 84/154 + 231/154 - 220/154 =

308/154 + 315/154 - 220/154 =

623/154 - 220/154 =

403/154.

D)4/5 - 1/2 - 2/3 + 6/7 + 10/8 =

Igualando os denominadores:

210/840 - 420/840 - 560/840 + 720/840 + 1.050/840 =

- 210/840 + 160/840 + 1.050/840 =

- 50/840 + 1.050/840 =

1.000/840 = 25/21.

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