Question

Reduza a uma única potencia

Answer 1

Resposta:

Explicação passo-a-passo:

a) $\frac{2^2-2^3}{2^4} =\frac{4-8}{16}=-\frac{4}{16}=-\frac{1}{4}=-\frac{1}{2^2}=-2^{-2}$

b) $\frac{3-3^4}{3^3}=\frac{3}{3^3}-\frac{3^4}{3^3}=3^{(1-3)}-3^{(4-3)}=3^{-2}-3^1=\frac{1}{3^2}-3=\frac{1}{9}-3=\frac{1-27}{9}=-\frac{26}{9}$

c) $\frac{10\ {\cdot}\ 10^3}{10^4}=\frac{10^4}{10^4}=1$

d) $2^4\ {\cdot}\ 2\ {\cdot}\ 2^2=2^{(4+1+2)}=2^7$

e) $10^3\ {\cdot}\ 10^5\ {\cdot}\ 10^2=10^{(3+5+2)}=10^10$

f) $\frac{2^3}{2}=2^3\ {\cdot}\ 2^{-1}=2^{(3+(-1))}=2^2$

g) $\frac{4^3{\cdot}4^5}{4^2}=4^{(3+5)}\ {\cdot}\ 4^{-2}=4^{(8+(-2))}=4^6$