Question

que numero elevado a -3 da 8,000

Answer 1

$\boxed{\boxed{\boxed{Ola\´ \: \: Afonso} }}}}$

• Interprete o problema:
$x^{-3} = 8000 \\ \\ \Leftrightarrow \frac{1}{x^3} = 8000 \\ \\ \Leftrightarrow 1 = 8000x^3 \\ \\ \Leftrightarrow x^3 = \frac{1}{8000} \\ \\ \Leftrightarrow x = \sqrt[3]{ \frac{1}{8000} } \\ \\ \Leftrightarrow x = \sqrt[ \cancel{3} ]{ \frac{1}{20^{\cancel{3} } } }$

$\Leftrightarrow \boxed{\boxed{x = \frac{1}{20}} }} \end{array}\qquad\checkmark$


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Answer 2

vamos lá !

que numero elevado a -3 da 8,000

${x}^{ - 3} = 8.000 \\ \\ {x}^{ - 3} = 8 \times 1000 \\ \\ {x}^{ - 3} = {2}^{3} \times {10}^{3} \\ \\ {x}^{ - 3} = ( {2 \times 10})^{3} \\ \\ {x}^{ - 3} = ( {20})^{3} \\ \\ \frac{1}{ {x}^{3} } = ( {20})^{ 3} \\ \\ {x}^{3} = \frac{1}{ {20}^{3} } \\ \\ x = \sqrt[3]{ \frac{1}{( {20})^{3} } } \\ \\ x = \frac{1}{20}$
espero ter ajudado!

bom dia !