Question

Racionalize
2/3 + √3

Answer 1

$\frac{2}{3+ \sqrt{3}} * \frac{3- \sqrt{3} }{3- \sqrt{3} } = \frac{6-2 \sqrt{3} }{9-3 \sqrt{3}+3 \sqrt{3} - \sqrt{9} } = \frac{6-2 \sqrt{3} }{9-3} = \frac{6-2 \sqrt{3} }{6} = \frac{3- \sqrt{3} }{3}$