Question

Racionalizando o denominador acima ( na foto) ,temos:

● b
● d
● a
● c​

Answer 1

$\boxed{\begin{array}{l}\sf Dado~o~radical~\sqrt[\sf n] {\sf a^m}\\\sf o~fator~racionalizante~\acute e~dado~por~\sqrt[\sf n]{\sf a^{n-m}}\end{array}}$

$\boxed{\begin{array}{l}\sf c\acute alculo~do~fator~racionalizante:\\\sf \sqrt[\sf 11]{2^{11-9}}=\sqrt[\sf11]{2^2}\\\sf\dfrac{4}{\sqrt[11]{\sf 2^9}}\cdot\dfrac{\sqrt[\sf11]{2^2}}{\sqrt[\sf11]{\sf2^2}}\\\sf\dfrac{4\sqrt[\sf11]{4}}{\sqrt[\sf\diagdown\!\!\!\!\!11]{\sf2^{\diagdown\!\!\!\!\!\!11}}}\\\sf=\dfrac{4\sqrt[\sf11]{4}}{2}=2\sqrt[\sf11]{\sf4}\end{array}}$