Question

Questão sobre funções (matemática) ...30 PONTOS

Answer 1

$f(x)=\dfrac{2x-6}{x-2}+\dfrac{1}{3}$

$f(x)=\dfrac{4}{3}$

$\dfrac{2x-6}{x-2}+\dfrac{1}{3}=\dfrac{4}{3}$

$\dfrac{2x-6}{x-2}=\dfrac{4}{3}-\dfrac{1}{3}$

$\dfrac{2x-6}{x-2}=1$

$2x-6=x-2$

$2x-x=6-2$

$x=4$