Question

que valor das expressoes (3^0,333...)^9 + (2^0,222...)^18 e (4^0,333...) +(2^0,222...)^18 sao respectivamente: a) 31 e 80 b)43 e 80 c) 31 e 70 d)43 e 70 e) 31 e 90

Answer 1

Resposta:

$123$

Explicação passo-a-passo:

$(3^{\frac{3}{9}})^9} + (2^{\frac{2}{9}})^{18}} + (4^{\frac{3}{9}})^{9}} + (2^{\frac{2}{9}})^{18}}$

$(3^{\frac{3.9}{9}})} + (2^{\frac{2.18}{9}})} + (4^{\frac{3.9}{9}})} + (2^{\frac{2.18}{9}})}$

$3^{3} + 2^{4} + 4^{3} + 2^{4}$

$27 + 16 + 64 + 16$

$123$

Espero ter ajudado !!!