Question

qual é as relaçoes fundamentas da trigonometria?

    
cosx*tgx*cossecx=1

tg2x*cossec2x=1+tg2x

 

Answer 1

Olá, Misleide.

 

$<var>a)\ cos\,x \cdot tg\,x\cdot cossec\,x=cos\,x \cdot \frac{sen\,x}{cos\,x}\cdot \frac{1}{sen\,x}=1 \\\\\\ b)\ tg^2x \cdot cossec^2x=\frac{sen^2x}{cos^2x} \cdot \frac{1}{sen^2x}=\frac{1}{cos^2x}=\frac{sen^2x+cos^2x}{cos^2x}=\\\\=\frac{sen^2x}{cos^2x}+\frac{cos^2x}{cos^2x}=tg^2x+1=1+tg^2x</var>$