Question

Preciso de ajuda nessas 2 questões

$\sqrt{\frac{1}{25} } : \sqrt{\frac{4}{36} } .\sqrt{\frac{81}{9} }$
$\sqrt{1 + \frac{11}{25}}: \frac{5}{6}$

Answer 1

Resposta:

$\sqrt{{1\over25}} \div\sqrt{{4\over36}} \times\sqrt{{81\over9}} =\\ \\ {1\over5}\div{2\over6}\times{9\over3}=\\ \\ {1\over5}\times{6\over2}\times{9\over3}=\\ \\ {54\over30}=~~simplificando~~{54:6\over30:6}={9\over5}$

$\sqrt{1+{11\over25}}\div{5\over6}}=\\ \\ \sqrt{{25+11\over25}}\div{5\over6}} =\\ \\ \sqrt{{36\over25}} \div{5\over6}=\\ \\ {6\over5}\times{6\over5}={36\over25}$