Question

(PG) Interpole 4 meios geométricos entre 3 e 96.

Answer 1

3_ _ _ _96
a1=3
a6=96
an=a1.q^(6-1)
96=3.q^5
3q^5=96
q^5=96/3
q^5 =32
q^5=2^5 => $q = \sqrt[5]{2^5}$=> q=2

PG(3 6 12 24 48 96)