Question

os 5primeiro termo de a1=12r=7

Answer 1

P.A

$a_1=12 \\ r=7 \\ \\ a_2=a_1+r \\ a_2=12+7=19 \\ \\ a_3=a_1+2r \\ a_3=12+2(7)=12+14=26 \\ \\ a_4=a_1+3r \\ a_4=12+3(7)=12+21=33 \\ \\ a_5=a_1+4r \\ a_5=12+4(7)=12+28=40 \\ \\ \\ P.A=(12,19,26,33,40)$