Question

Obtenha a equação da reta que passa pelo ponto (-2, 1) e tem coeficiente linear igual a 4 (b = 4).

Answer 1

$\large\boxed{\begin{array}{l}\underline{\sf equac_{\!\!,}\tilde ao\,da\,reta}\\\rm y=ax+b\\\rm a\longrightarrow coeficiente\,angular\\\rm b\longrightarrow coeficiente\,linear\\\rm A(-2,1)\implies x=-2~~y=1\\\rm y=ax+b\\\rm 1=a\cdot(-2)+4\\\rm -2a+4=1\\\rm 2a=4-1\\\rm 2a=3\\\rm a=\dfrac{3}{2}\\\\\rm y=\dfrac{3}{2}x+4\longrightarrow equac_{\!\!,}\tilde ao\,procurada\end{array}}$