Question

O ponto médio M do segmento A(7,8) e B(11,16) é:

M(4,8)
M(9,12)
M(4,4)
M(2,8)​

Answer 1

$x_M=\frac{x_A+x_B}{2}=\frac{7+11}{2}=\frac{18}{2}=9$

$y_M=\frac{y_A+y_B}{2}=\frac{8+16}{2}=\frac{24}{2}=12$

$M(9,12)$