Question

o Log5 625 + Log 100 - Log3 27?

Answer 1

$log_{5}(625) + log(100) - log_{3}(27) =$
Calculando os logaritmos:
$log_{5}(625) \\ {5}^{x} = 625 \\ 5 {}^{x} = {5}^{4} \\ x = 4$
$log_{5}(625) = 4$
$log_{10}(100) = \\ 10 {}^{x} = 100 \\ {10}^{x} = 10 {}^{2} \\ x = 2$
$log(100) = 2$
$log_{3}(27) = \\ {3}^{x} = 27 \\ {3}^{x} = 3 {}^{3} \\ x = 3$
$log_{3}(27) = 3$
Substituindo:
$log_{5}(625) + log(100) + log_{3}(27) = \\ 4 + 2 - 3 = \\ 3$