Na divisão de p(x)=2x³+3x²-x+5 por D(x)=x²-2x+1 determine o quociente e o resto
Soluções para a tarefa
Respondido por
1
x²-2x+1 · 2x = 2x³+4x²-2x
x²-2x+1 · 7= 7x²+14x-7
Q= 2x+7
R=11x-2
x²-2x+1 · 7= 7x²+14x-7
Q= 2x+7
R=11x-2
Respondido por
5
Olá ^^
vamos usar o método da chave, que consiste em dividir e voltar multiplicando debaixo do divisor, com o sinal invertido, acompanhe:
![~~~2x^3+3x^2-x+5~~|~~x^2-2x+1\\
-2x^3+4x^2-2x~~~~~~~~~~2x+7\\
---------\\
~~~~0+7x^2~~-~~3x+5\\
~~~~~~-7x^2~~+14x-7\\
~~~~~~~~~-------\\
~~~~~~~~~~0~~~~~+11x-2\\\\
\Large\boxed{\boxed{Q(x)=2x+7~~~~e~~~~R(x)=11x-2}} ~~~2x^3+3x^2-x+5~~|~~x^2-2x+1\\
-2x^3+4x^2-2x~~~~~~~~~~2x+7\\
---------\\
~~~~0+7x^2~~-~~3x+5\\
~~~~~~-7x^2~~+14x-7\\
~~~~~~~~~-------\\
~~~~~~~~~~0~~~~~+11x-2\\\\
\Large\boxed{\boxed{Q(x)=2x+7~~~~e~~~~R(x)=11x-2}}](https://tex.z-dn.net/?f=%7E%7E%7E2x%5E3%2B3x%5E2-x%2B5%7E%7E%7C%7E%7Ex%5E2-2x%2B1%5C%5C%0A-2x%5E3%2B4x%5E2-2x%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E2x%2B7%5C%5C%0A---------%5C%5C%0A%7E%7E%7E%7E0%2B7x%5E2%7E%7E-%7E%7E3x%2B5%5C%5C%0A%7E%7E%7E%7E%7E%7E-7x%5E2%7E%7E%2B14x-7%5C%5C%0A%7E%7E%7E%7E%7E%7E%7E%7E%7E-------%5C%5C%0A%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E0%7E%7E%7E%7E%7E%2B11x-2%5C%5C%5C%5C%0A%5CLarge%5Cboxed%7B%5Cboxed%7BQ%28x%29%3D2x%2B7%7E%7E%7E%7Ee%7E%7E%7E%7ER%28x%29%3D11x-2%7D%7D)
Tenha ótimos estudos ;D
vamos usar o método da chave, que consiste em dividir e voltar multiplicando debaixo do divisor, com o sinal invertido, acompanhe:
Tenha ótimos estudos ;D
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