Question

Me ajudem nesta questão =)

6x² + 11x - 10 = 0

Answer 1

$6x^{2}+11x-10=0~~~~~~~(a=6~~~~~~b=11~~~~~~c=-10)\\\\\Delta=b^{2}-4ac\\\Delta=11^{2}-4\cdot6\cdot(-10)\\\Delta=121+240\\\Delta=361\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}=\dfrac{-11\pm\sqrt{361}}{2\cdot6}=\dfrac{-11\pm19}{12}$

Então, temos como raízes:

$x'=\dfrac{-11+19}{12}=\dfrac{8}{12}~~~~\therefore~~~~\boxed{\boxed{x'=\dfrac{2}{3}}}\\\\\\x'=\dfrac{-11-19}{12}=-\dfrac{30}{12}~~~~\therefore~~~~\boxed{\boxed{x'=-\dfrac{5}{2}}}$