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A) 8+4+1+2+4+2 = 21
B) 5+12+3+4+8+9 = 41
B) 5+12+3+4+8+9 = 41
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Boa noite Eduardo
Solução!
Vamos usar essa formula para calcular o volume de madeira,já que as peças tem o formato de um cilindro.
![V= \pi .r^{2}.h V= \pi .r^{2}.h](https://tex.z-dn.net/?f=V%3D+%5Cpi+.r%5E%7B2%7D.h+)
Peça A
![r_{1}=4 ~~~~h_{1}=4 \\\\r_{2}=2~~~~h_{2}=2 \\\\ r_{3}=1~~~~h_{1}=1 r_{1}=4 ~~~~h_{1}=4 \\\\r_{2}=2~~~~h_{2}=2 \\\\ r_{3}=1~~~~h_{1}=1](https://tex.z-dn.net/?f=r_%7B1%7D%3D4+%7E%7E%7E%7Eh_%7B1%7D%3D4+%5C%5C%5C%5Cr_%7B2%7D%3D2%7E%7E%7E%7Eh_%7B2%7D%3D2+%5C%5C%5C%5C+r_%7B3%7D%3D1%7E%7E%7E%7Eh_%7B1%7D%3D1)
![V_{t}= \pi .(4)^{2} .4+ \pi (2)^{2}.2 + \pi 1(1) ^{2} \\\\\\ V_{t}=\pi .16 .4+ \pi 4.2+ \pi 1.1\\\\\\ V_{t}=64 \pi +8 \pi +1 \pi \\\\\\ V_{t}= \pi (64+8+1) \\\\\\ V_{t}= \pi 73cm^{3} V_{t}= \pi .(4)^{2} .4+ \pi (2)^{2}.2 + \pi 1(1) ^{2} \\\\\\ V_{t}=\pi .16 .4+ \pi 4.2+ \pi 1.1\\\\\\ V_{t}=64 \pi +8 \pi +1 \pi \\\\\\ V_{t}= \pi (64+8+1) \\\\\\ V_{t}= \pi 73cm^{3}](https://tex.z-dn.net/?f=V_%7Bt%7D%3D+%5Cpi+.%284%29%5E%7B2%7D+.4%2B+%5Cpi+%282%29%5E%7B2%7D.2+%2B+%5Cpi+1%281%29+%5E%7B2%7D+%5C%5C%5C%5C%5C%5C+V_%7Bt%7D%3D%5Cpi+.16+.4%2B+%5Cpi+4.2%2B+%5Cpi+1.1%5C%5C%5C%5C%5C%5C+V_%7Bt%7D%3D64+%5Cpi+%2B8+%5Cpi+%2B1+%5Cpi++%5C%5C%5C%5C%5C%5C+V_%7Bt%7D%3D+%5Cpi+%2864%2B8%2B1%29+%5C%5C%5C%5C%5C%5C+V_%7Bt%7D%3D+%5Cpi+73cm%5E%7B3%7D+)
![\boxed{ \boxed{Resposta:V_{t}=\pi73cm^{3}}} \boxed{ \boxed{Resposta:V_{t}=\pi73cm^{3}}}](https://tex.z-dn.net/?f=%5Cboxed%7B+%5Cboxed%7BResposta%3AV_%7Bt%7D%3D%5Cpi73cm%5E%7B3%7D%7D%7D)
Peça B
![r_{1}=2,5~~~~h_{1}=12\\\\ r_{2}=1,5~~~~h_{1}=4 \\\\ r_{3}=4,5~~~~h_{3}=8 r_{1}=2,5~~~~h_{1}=12\\\\ r_{2}=1,5~~~~h_{1}=4 \\\\ r_{3}=4,5~~~~h_{3}=8](https://tex.z-dn.net/?f=r_%7B1%7D%3D2%2C5%7E%7E%7E%7Eh_%7B1%7D%3D12%5C%5C%5C%5C+r_%7B2%7D%3D1%2C5%7E%7E%7E%7Eh_%7B1%7D%3D4+%5C%5C%5C%5C+r_%7B3%7D%3D4%2C5%7E%7E%7E%7Eh_%7B3%7D%3D8)
![V_{t}= \pi (2,5)^{2}.12+ \pi .(1,5)^{2}.4+ \pi .(4,5)^{2}.8 \\\\\ V_{t}= \pi .6,25.12+ \pi.2,25.4+ \pi .20.25.8 \\\\\\ V_{t}=75 \pi +9 \pi +162 \pi \\\\\\ V_{t}= \pi (75+9+162) \\\\\\V_{t}= \pi 246cm ^{3} V_{t}= \pi (2,5)^{2}.12+ \pi .(1,5)^{2}.4+ \pi .(4,5)^{2}.8 \\\\\ V_{t}= \pi .6,25.12+ \pi.2,25.4+ \pi .20.25.8 \\\\\\ V_{t}=75 \pi +9 \pi +162 \pi \\\\\\ V_{t}= \pi (75+9+162) \\\\\\V_{t}= \pi 246cm ^{3}](https://tex.z-dn.net/?f=V_%7Bt%7D%3D+%5Cpi+%282%2C5%29%5E%7B2%7D.12%2B+%5Cpi+.%281%2C5%29%5E%7B2%7D.4%2B+%5Cpi+.%284%2C5%29%5E%7B2%7D.8+%5C%5C%5C%5C%5C%C2%A0V_%7Bt%7D%3D+%5Cpi+.6%2C25.12%2B+%5Cpi.2%2C25.4%2B+%5Cpi+.20.25.8+%5C%5C%5C%5C%5C%5C+V_%7Bt%7D%3D75+%5Cpi+%2B9+%5Cpi+%2B162+%5Cpi+%5C%5C%5C%5C%5C%5C+V_%7Bt%7D%3D+%5Cpi+%2875%2B9%2B162%29+%5C%5C%5C%5C%5C%5CV_%7Bt%7D%3D++%5Cpi+246cm+%5E%7B3%7D)
![\boxd{\boxed{V_{t}=\pi246 cm ^{3}}} \boxd{\boxed{V_{t}=\pi246 cm ^{3}}}](https://tex.z-dn.net/?f=%5Cboxd%7B%5Cboxed%7BV_%7Bt%7D%3D%5Cpi246+cm+%5E%7B3%7D%7D%7D)
Boa noite!
Bons estudos!
Solução!
Vamos usar essa formula para calcular o volume de madeira,já que as peças tem o formato de um cilindro.
Peça A
Peça B
Boa noite!
Bons estudos!
eduardomesomo:
resolução muito complicado não entendi nada faça uma mais fácil obrigado
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