Question

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Answer 1

Resposta:

$a)\\\\ (2x^{2} -9x+2)+(3x^{2} +7x-1)=\\ \\ 2x^{2} +3x^{2} -9x+7x+2-1=\\ \\ 5x^{2} -2x+1\\ \\ \\ b)\\ \\ (5x^{2} +5x-8)+(-2x^{2} +3x-2)=\\ \\ 5x^{2} -2x^{2} +5x+3x-8-2=\\ \\ 3x^{2} +8x-10\\ \\ \\ c)\\ \\ (3x-6y+4)+(4x+2y-2)=\\ \\ 3x+4x-6y+2y+4-2=\\ \\ 7x-4y+2$

$d)\\ \\ (5x^{2} -7x+2)+(2x^{2} +7x-1)=\\ \\ 5x^{2} +2x^{2} -7x+7x+2-1=\\ \\ 7x^{2} +1\\ \\ \\ e)\\ \\ (4x+3y+1)+(6x-2y-9)=\\ \\ 4x+6x+3y-2y+1-9=\\ \\ 10x+y-8\\ \\ \\ f)\\ \\ (2x^{3} +5x^{2} +4x)+(2x^{3} -3x^{2} +x)=\\ \\ 2x^{3} +2x^{3} +5x^{2} -3x^{2} +4x+x=\\ \\ 4x^{3} +2x^{2} +5x\\ \\ \\ g)\\ \\ (5x^{2} -2ax+a^{2} )+(-3x^{2} +2ax-a^{2} )=\\ \\ 5x^{2} -3x^{2} -2ax+2ax+a^{2} -a^{2} =\\ \\ 2x^{2} \\ \\ \\ h)\\ \\ (y^{2} +3y-5)+(-3y+7-5y^{2} )=\\ \\ y^{2} -5y^{2} +3y-3y-5+7=\\ \\ -6y^{2} +2$

$i)\\ \\ (x^{2} -5x+3)+(-4x^{2} -2x)=\\ \\ x^{2} -4x^{2} -5x-2x+3=\\ \\ -5x^{2} -7x+3\\ \\ \\ j)\\ \\ (9x^{2} -4x-3)+(3x^{2} -10)=\\ \\ 9x^{2} +3x^{2} -4x-3-10=\\ \\ 12x^{2} -4x-13$