Question

loga = 2 e logb = –logc = 6. Calcule:
$log( \frac{ {a}^{2} \times \: {b}^{2} }{ {c}^{3} } )$
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Answer 1

Resposta:

log a²+log b² - log c³

2*log a+ 2*log b-2*log c

4+12-2*(-6)

=16+12=28