Question

log3 2x−2 + log3 2x+2 =2.log3x

Answer 1

$log_{3} (2x-2) + log_{3} (2x+2) = 2.log_{3} x log_{3} (2x-2).(2x+2) = log_{3} (x²) (2x - 2).(2x+2) = (x²) 4x² - 4 = x² 3x² = 4 x² = 4/3 x1 = 2/ \sqrt{3}$

X1 = $2\sqrt{3} /3$
X1 = -$2 \sqrt{3} /3$