Question

log p 81=2 qual valor de p?

Answer 1

Assumindo que "p" seja a base do logaritmo, basta utilizarmos a definição:

$log_{_p}81~=~2\\\\\\81~=~p^2\\\\\\Fatorando~81\rightarrow~81=9\cdot9=\boxed{9^2}\\\\\\9^2~=~p^2\\\\\\Igualdade~de~potencias~de~mesmo~expoente\\\\\\9^{2\!\!\!\backslash}~=~p^{2\!\!\!\backslash}\\\\\\\boxed{p~=~9}$