Question

log 1/49 7 = x -> 1/49¨x = 7 ... Como resolver ?

Answer 1

seria Log1/49(7)=x
7=(1/49)^x
7=(1/7²)^x
7=(7^-2)^x
7=7^-2x
7^1=7^-2x
1=-2x
X=-1/2
..
espero ter ajudado o simbolo "^'' significa elevado...

Answer 2

.
$\log_{ \frac{1}{49} }{7}=x \\ \\ ( \frac{1}{49})^x=7 \\ \\ ( \frac{1}{7} )^{2x}=7^1 \\ \\ 7^{-2x}=7^1 \\ \\ -2x=1 \\ 2x=-1 \\ \\ x=- \frac{1}{2}$