Question

integral definida de 1/x^2 intervalo [1,7]

Answer 1

$\int\limits^7_1 { \dfrac{1}{x^2} } \, dx \\\\ \int\limits^7_1 { x^{-2} \,dx \\\\ \int\limits^7_1 { \dfrac{x^{-2+1}}{-1} \, dx \\\\ \int\limits^7_1 { \dfrac{x^{-1}}{-1} \, dx \\\\ \int\limits^7_1 { \dfrac{-1}{x} \, dx \\\\ \dfrac{-1}{7} - \dfrac{-1}{1}\\\\ \dfrac{-1}{7} + 1\\\\ \dfrac{6}{7}$

Espero que tenha entendido!