Question

Importante de mais plzzzzz!!!!!

Answer 1

Resolvendo:

$Soma: \frac{1}{3} \:.\:A+\frac{1}{2} \:.\:B\\\\Calculando\:\:separadamente:\\\\\frac{1}{3} \:.\:A=\frac{1}{3} \:.\:\left[\begin{array}{ccc}6&-9\\12&3\\\end{array}\right] \\\\\\\left[\begin{array}{ccc}6\:.\:\frac{1}{3} &-9\:.\:\frac{1}{3} \\12\:.\:\frac{1}{3} &3\:.\:\frac{1}{3} \\\end{array}\right] =\left[\begin{array}{ccc}\frac{6}{3} &-\frac{9}{3} \\\\\frac{12}{3} &\frac{3}{3} \\\end{array}\right] \\\\\\\left[\begin{array}{ccc}2&-3\\4&1\\\end{array}\right]$

$\frac{1}{2} \:.\:B=\frac{1}{2} \:.\:\left[\begin{array}{ccc}10&4\\-8&6\\\end{array}\right] \\\\\\\left[\begin{array}{ccc}10\:.\:\frac{1}{2} &4\:.\:\frac{1}{2} \\-8\:.\:\frac{1}{2} &6\:.\:\frac{1}{2} \\\end{array}\right] =\left[\begin{array}{ccc}\frac{10}{2} &\frac{4}{2} \\\\\frac{-8}{2} &\frac{6}{2} \\\end{array}\right] \\\\\\\left[\begin{array}{ccc}5&2\\-4&3\\\end{array}\right]$

$\frac{1}{3} \:.\:A+\frac{1}{2} \:.\:B=\\\\\\\left[\begin{array}{ccc}2&-3\\4&1\\\end{array}\right] +\left[\begin{array}{ccc}5&2\\-4&3\\\end{array}\right]=\\\\\\\left[\begin{array}{ccc}7&-1\\0&4\\\end{array}\right]$

Resposta:

$\left[\begin{array}{ccc}7&-1\\0&4\\\end{array}\right]$

Espero ter ajudado!

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