Question

faça X² - 8x + 12 = 0 com delta e bhaskara

Answer 1

Δ = b² - 4ac
Δ = -8² - 4.1.12
Δ = 64 - 48
Δ = 16

x = - b +-√Δ/2a
x = 8 +-√16/2
x = 8 +- 4/2
x' = 8 +4/2
x' = 12/2 = 6
x" = 8-4/2
x" = 4/2 = 2   ok

Answer 2

1)Calculando o Δ da equação
Δ = b2 - 4.a.c 
Δ = -82 - 4 . 1 . 12 
Δ = 64 - 4. 1 . 12 
Δ = 16

2) Aplicando Bhaskara:

x = (-b +- √Δ)/2a

x' = (--8 + √16)/2.1   
x' = + 8 + 4 / 2
x' = 12/2
x' = 6
x'' = (--8 - √16)/2.1
x'' = 8 - 4 / 2
x'' = 4/2
x" = 2