Question

Escreva uma PG de 8 termos em que a1 = 6 e q = -4

Answer 1

$a_{1} = 6\\\\q=-4\\\\n=8\\\\\ a_{2}= a_{1}*q\to a_{2}=6*(-4)\to a_{2}= -24\\\\ a_{3}= a_{2}*q\to a_{3}=-24*(-4)\to a_{3} =96\\\\ a_{4}= a_{3}*q\to a_{4}= 96*(-4)\to a_{4}=-384\\\\ a_{5}= a_{4}*q\to a_{5} = -384*(-4)\to a_{5}=1536\\\\ a_{6}= a_{5}*q\to a_{6} = 1536*(-4)\to a_{6} = -6144\\\\ a_{7} = a_{6} *q\to a_{7}=-6144*(-4)\to a_{7}= 24576\\\\ a_{8}= a_{7}*q\to a_{8}= 24576*(-4)\to a_{8}= -98304\\\\\\PG=(6, -24, 96, -384, 1536, -6144, 24576, -98304)$