Question

equações de Bhaskara
x^2-8x+12=0​

Answer 1

Resposta:

x² - 8x + 12 = 0

delta = b² - 4.a.c

a = 1

b = -8

c = 12

delta = (-8)² - 4.1.12

delta = 64 - 48

delta = 16

x = -b ± √delta/2.a

x = -(-8) ± √16/2.1

x = 8 ± 4/2

x = 8 - 4/2 = 4/2 = 2

x = 8 + 4/2 = 12/2 = 6

s={ 2, 6 }