Question

então a area sobrada da figura e=

Answer 1

$\int\limits^2_0 {4-x^2} \, dx =4x -\frac{x^3}{3} \left\begin{array}{ccc}\end{array}\right]^2_0$
$\left[\begin{array}{ccc}4(2)- \frac{2^3}{3} \end{array}\right] - \left[\begin{array}{ccc}4(0)- \frac{0^3}{3} \end{array}\right]=> 8- \frac{8}{3}=>\frac{16}{3}$