Question

Encontre as raízes das funções quadráticas!
$16=9x^{2}$

Answer 1

$16=9x^{2}\\9x^{2}=16\\9x^{2}-16=0\\9x^{2}+0x-16=0\\\\(a=9~~~b=0~~~c=-16)\\\\\Delta=b^{2}-4ac\\\Delta=0^{2}-4\cdot9\cdot(-16)\\\Delta=0-(-576)\\\Delta=576\\\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}=\dfrac{0\pm\sqrt{576}}{2\cdot9}=\dfrac{\pm24}{18}~~~simplificando~~~x=\pm\dfrac{4}{3}$

Raízes:

$\boxed{\boxed{x'=\dfrac{4}{3}}}\\\\\\\boxed{\boxed{x''=-\dfrac{4}{3}}}$

Answer 2

Explicação passo-a-passo:

16=9x2

9x2=16

x2=16/9

x=√16/9

x=4/3 ou x=-4/3

S={-4/3;4/3}

ok!