Question

Encontre a solução da equação
(X+1)×(x-5)=0

Answer 1

(x+1)x(x-5)=0

2x-4=0

2x=0+4

x=0,25

Answer 2

( x + 1)(x - 5 )=0

calculando por Baskara

$x^2-5x+x-5=0 \\ x^{2} -4x-5=0 \\ \\ a=1 \\ b=-4 \\ c=-5 \\ \\ \Delta=b^2-4ac \\ \Delta=(-4)^2-4(1)(-5) \\ \Delta=16+20 \\ \Delta=36 \\ \\ x= \frac{-b\pm \sqrt{\Delta} }{2a} =~~ \frac{-(-4)\pm \sqrt{36} }{2} = \frac{4\pm6}{2} \\ \\ x'= \frac{4+6}{2} = \frac{10}{2} =5 \\ \\ x"= \frac{4-6}{2} =- \frac{2}{2} =-1 \\ \\ S=\{-1,5\}$