Question

Em um triângulo retângulo a hipotenusa mede 14 cm, e um dos catetos mede 5 raíz de 3 cm . Determine a medida do outro cateto.

Answer 1

$14^2=(5\sqrt3)^2+x^2\\\\ 196=75+x^2\\\\ x^2=121\\\\ x=\sqrt{121}\\\\ \boxed{x=11\;cm}$

Answer 2

$h^2=c^2+c^2\\14^2=(5\sqrt3)^2+c^2\\196=25*3+c^2\\196=75+c^2\\c^2=196-75\\c^2=121\\c=\sqrt{121}\\c=11cm$