em cada caso calcule o coeficiente angular e linear da reta que passa pelos pontos dados : a - (1,0) e (-2,0) b (1,2) e (2,1) c (1,-1) e (2,-3)
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(1,0) e (-2,0) coef.angular
a = 0 - 0 ==> a = 0 ==> a = 0
-2 - 1 - 3
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a = 0 e P (1,0) coef.linear
y = ax + b ==> 0.1 + b = 0 ==> b = 0
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b (1,2) e (2,1) coef.angular
a = 1 - 2 ==> a = - 1 ==> a = - 1
2 - 1 1
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a = - 1 e P (1,2) coef.linear
y = ax + b ==> (-1).1 + b = 2 ==> b = 1 + 2 ==> b = 3
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c (1,-1) e (2,-3) coef. angular
a = - 3 - (-1) ==> a = 3+1 ==> a = 4
2 - 1 1
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a = 4 e P (1,- 1) coef. linear
y = ax + b ==> 4.1 + b = - 1 ==> b = - 1 - 4 ==. b = - 5
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a = 0 - 0 ==> a = 0 ==> a = 0
-2 - 1 - 3
================================================
a = 0 e P (1,0) coef.linear
y = ax + b ==> 0.1 + b = 0 ==> b = 0
===============================================
b (1,2) e (2,1) coef.angular
a = 1 - 2 ==> a = - 1 ==> a = - 1
2 - 1 1
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a = - 1 e P (1,2) coef.linear
y = ax + b ==> (-1).1 + b = 2 ==> b = 1 + 2 ==> b = 3
===============================================
c (1,-1) e (2,-3) coef. angular
a = - 3 - (-1) ==> a = 3+1 ==> a = 4
2 - 1 1
================================================
a = 4 e P (1,- 1) coef. linear
y = ax + b ==> 4.1 + b = - 1 ==> b = - 1 - 4 ==. b = - 5
===============================================
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