Question

Dormula de Bhaskara x²-6x+5=0

Answer 1

Resolução:

x²- 6x + 5= 0

a = 1

b = - 6

c = 5

Δ = b² - 4.a.c  

Δ = (- 6)² - 4 . 1 . 5  

Δ = 36 - 20  

Δ = 16

x = (- b +- √Δ)/2a

x = (+ 6 +- √16)/2 . 1

x = (6 +- 4)/2

x' = (6 + 4)/2

x' = 10/2

x' = 5

x'' = (6 - 4)/2

x'' = 2/2

x'' = 1

Answer 2

a=1

b=-6

c=5

Δ=$b^{2} -4.a.c$

Δ=$(-6)^{2} -4.1.5$

Δ=$36-20$

Δ=$16$

$x1=\frac{-b+\sqrt{16}}{2.a}=\frac{6+4}{2.1}=\frac{10}{2}=5$

$x2=\frac{-b-\sqrt{16}}{2.a}=\frac{6-4}{2.1}=\frac{2}{2}=1$