Question

Divisão de numeros complexosZ1/Z2Z1=3+iZ2=2+2i

Answer 1

Z1 =  3 + i; Z2 = 2 + i

$\frac{ Z_{1} }{ Z_{2} } =\frac{3+i}{2+i} = \frac{(3+i)(2-i)}{(2+i)(2-i)} = \frac{6-3i+2i-i^2}{4-i^2} = \frac{6-i-(-1)}{4-(-1)} =\frac{7-i}{5}$$= \frac{7}{5} - \frac{1}{5}i$