Question

     Determine o valor de x nos triângulos abaixo

Answer 1

a)

$<var>tan 60=\frac{5}{x}\rightarrow \sqrt3=\frac{5}{x}\rightarrowx=\frac{5}{\sqrt3}=\frac{5\sqrt3}{3}</var>$

 

 

b)

 

 

$<var>sen 45=\frac{x}{3\sqrt2}\rightarrow \frac{\sqrt2}{2}=\frac{x}{3\sqrt2}\rightarrow x=\frac{3\sqrt2\sqrt2}{2}=\frac{6}{2}=3</var>$