Question

Determine o valor de delta Δ nas equacoes abaixo. ( x + 7)( x – 1) = 0 b) ( 6 – 4t)( 2 – 2t) = 0 C) ( x + 1)( 3x – 2) = 0 d) ( 4 – 3w)( 2 + w) = 0

Answer 1

Resposta:

A) (x+7)×(x-1)=0

x²-1x+7x-7=0

x²+6x-7=0

a= 1 b= 6 c= -7

delta= b²-4×a×b

delta= 6²-4×1×-7

delta= 36-4×-7

delta= 36-28

delta= 8

B) ( 6-4t)×(2-2t)=0

12-12t-8t+8t²=0

13-20t+8t²=0

a= 8 b= -20 c= 12

delta= b²-4×a×c

delta= -20²-4×8×12

delta= 400-4×8×12

delta= 400-4×96

delta=400- 384

delta= 16

C) ( x+1 )×( 3x -2 )=0

3x²-2x+3x-2=0

3x²+1x-2=0

a= 3 b= 1 c= -2

delta= b²-4×a×c

delta= 1²-4×3×-2

delta= 1 -4×-6

delta= 1+24

delta= 25

D) (4-3w)×(2 +w)=0

8+4w-6w-3w²=0

8 -2w -3w²=0

a= -3 b= -2 c= 8

delta= b²-4×a×c

delta=(-2)²-4×-3×8

delta= 4-4×-24

delta= 4+96

delta= 100

delta=