Question

Determine c=(cij) 3×3, onde cij= i³+ 4j².

Answer 1

Resposta:

Explicação passo-a-passo:

c11=1^3+4.1^2=1+4=5

c12=1^3+4.2^2=1+4.4=1+16=17

c13=1^3+4.3^2=1+4.9=1+36=37

c21=2^3+4.1^2=8+4.1=8+4=12

c22=2^3+4.2^2=8+4.4=8+16=24

c23=2^3+4.3^2=8+4.9=8+36=44

c31=3^3+4.1^2=27+4.1=27+4=31

c32=3^3+4.2^2=27+4.4=27+16=43

c33=3^3+4.3^2=27+4.9=27+36=63

|5   17    37|

|12  24  44|

|31  43  63|